Physics II note
Coulombs law
Electric Field
\(\vec{E} = \dfrac{\vec{F_0}}{q_0}\\\)
Where:
$\vec{E}$ is the electric field
$\vec{F_0}$ is the force experienced at a point in the electric field
$q_0$ is the Test charge
Electric Field of a Point Charge
\(F(x,y,z) = \dfrac{1}{4\pi\epsilon_0} \dfrac{q_1q_0}{r^2}\\ E(x,y,z) = 1\dfrac{F(x,y,z)}{q_0}\\ E_p(x,y,z) = \dfrac{1}{4\pi\epsilon_0} \dfrac{q_1}{r^2} u \\\) The electric field is measure in Newton/Coulomb
Superposition of Electric Fields generated by point charges
\[F= \sum_{i} F_i\]Eletric field computation: continuous distribution of charge
Line Charges
$dE = \dfrac{1}{4\pi\epsilon_0}\dfrac{q_i}{r^2_i}$
Disk charges
Cube charges
\[E = \int\dfrac{1}{4\pi\epsilon_0}\dfrac{dq}{r^2}u\]Charge density
Linear charge density
\[\lambda = \dfrac{q}{\mathscr{l}}\]A linear charge where \(y \gg l\) then it practically becomes a point charge
A linear charge where \(y \ll l\) then it is…
Surface charge density
\[\sigma = \dfrac{q}{\mathscr{l}^2}\]check what happens when the surface of the disk tends to $\infty$